2) If a reaction vessel contains 0.15 mol K2O2 and 0.10 mol H2O.
(Ar: K=39; O=16; H=1)
2 K2O2 + 2 H2O
4 KOH + O2
a. Which is the limiting reactant? Ans: H2O
b. Which is the reactant in excess? Ans: K2O2
c. How many grams of KOH will form? Ans:11.2
d. How many Liters of Oxygen gas will be released? Ans: 1.2